Question

Easy question..!

The base radius and height of a right circular cylinder are 5 cm and 10 cm. It's total surface area is

____________

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Answer 1

Step-by-step explanation:

Base (b)=5cm

Height (h)= 10cm

TSA of Cylinder= 2πrh+2πr2

=2×3.14×r×10+2×3.14×r×2

=6.28×r×12×3.14×r×2

=75.36×6.28

=473.2680

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Answer 2

Answer:

$\huge \fbox\red{AnSWer}$

Since we have given that

base radius = 5 cm

Height = 10 cm

So, the surface area of circular cylinder would be

$\pi \: r$

$\frac{22}{7} \times 5(5 + 10)$

$= \frac{22}{7} \times 5 \times 15$

$235.71$

Hence, its surface area would be 235.71 sq. cm.

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