Easy question this time!!
A cylinderical can containing pieces of fruit is filled to the top with syrup before being sealed. The base of the can has an area of 75 cm², and the height of the can is 10 cm. If 110 cm³ of syrup is needed to fill the can to the top, which is closest to total volume of pieces of fruits in can?
A) 7.5 cm³
B) 185 cm³
C) 640 cm³
D) 750 cm ³
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Answered by
9
Answer:
Given :-
- A cylinderical can containing pieces of fruit is filled to the top with syrup before being sealed. The base of the can has an area of 75 cm², and the height of the can is 10 cm. If 110 cm³ of syrup is needed to fill the can to the top.
Find Out :-
- The total volume of pieces of fruits in can?
Solution :-
For the cylindrical can,
- Area of base = πr² =75 cm²
- Height = h=10 cm
Volume of the cylindrical can :-
➙ πr²h
➙ 75 × 10
➙ 750 cm³
Volume of syrup= 110 cm³
Therefore,
Volume of fruits :-
➙ Volume of cylinder - Volume of syrup
➙ (750-110) cm³
➙ 640 cm³
Henceforth, the total volume of pieces of fruits in can is 640 cm³.
Answered by
34
★ Given :-
- Area of base of a can = 75 cm²
- Height of the can = 10 cm
- Volume of syrup in the can = 110 cm³
★ To Find :-
- Volume of the fruits in the can
★ Formula Used :-
★ Solution :-
We have already been provided with area of the base ( π r² ) which is 75 cm²
Now, we can simply multiply the height and the area of base of the can to get it's volume.
Now, we have been provided with volume of the syrup, and we know that,
=> Volume of can = volume of fruits + volume of syrup
Therefore, the volume of the fruits is .
I hope that it helps!
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