easy sum... pls explain this
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Answered by
1
P(x) = x^2 - 4
g(x) = x - 2
g(x) = 0
=> x - 2 = 0
=> x = 2
By Remainder theoram,
Remainder = (2)^2 - 4
= 4 - 4
= 0
Option (c) is correct...
g(x) = x - 2
g(x) = 0
=> x - 2 = 0
=> x = 2
By Remainder theoram,
Remainder = (2)^2 - 4
= 4 - 4
= 0
Option (c) is correct...
Answered by
0
Put x ka value = 2 ....as x-2 is given in x^2 -4 ....
You will get (2)^2 -4...
=4-4
=0
You will get (2)^2 -4...
=4-4
=0
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