Math, asked by Anonymous, 5 hours ago



Easy + Tricky Question!!

How many times does the digit 5 occur in tens place in the natural numbers from 100 to 1000?

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Answers

Answered by Aryan0123
37

Answer:

90 times

Step-by-step explanation:

In order to solve this question, let us see all the cases where 5 occurs in tens place.

The digit 5 occurs in tens place in the following cases:

  • 150, 151, 152, .... , 159 ---- 10 numbers
  • 250, 251, 252, .... , 259 ---- 10 numbers
  • 350, 351, 352, .... , 359 ---- 10 numbers
  • 450, 451, 452, .... , 459 ---- 10 numbers
  • 550, 551, 552, .... , 559 ---- 10 numbers
  • 650, 651, 652, .... , 659 ---- 10 numbers
  • 750, 751, 752, .... , 759 ---- 10 numbers
  • 850, 851, 852, .... , 859 ---- 10 numbers
  • 950, 951, 952, .... , 959 ---- 10 numbers

So the total number of times 5 occurs in tens place:

= 10 × 9

= 90

The digit 5 occurs in tens place 90 times in between the natural numbers from 100 to 1000

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