Question

Eccentricity of the hyperbola 16x2 – 3y2 –
32x - 12y -- 44 = 0 is​

Answer 1

Answer:

Given equation is 16x^2-3y^2-32x-12y-44=0

the simplified eqn is

3(x−1)^2− 16(y−2)^2=1

thereby, e^2=1+(a^2/b^2)

e^2=1+(4/√3)^2

e^2=19/3

e=√19/3