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A storage tank is to be made from a sheet of metal, 9 meters square, by cutting a square of side x meters from each corner and bending up the sides. What is the maximum volume of the tank, if the height of the tank must not exceed 3 meters ?
Answers
Answered by
4
Answer:
9×9 = 81
3×3 = 9
Now - Total - Perimeter
81-9 = 72
Answered by
0
Answer:
Maximum volume of the tank = 2 m³
Step-by-step explanation:
Assuming open Tank :
Metal sheet of metal 9 meters square
So the side of sheet metal = 3 m
A square cut form each side = x m
Then Base = (3 - 2x ) m
Height = x m
Volume = ( 3 - 2x)²x
V = (9 + 4x² - 12x)x
V = 4x³ - 12x² + 9x
dV/dx = 12x² - 24x + 9
dV/dx = 0
= 12x² - 24x + 9 = 0
= 4x² - 8x + 3 = 0
= 4x² - 6x - 2x + 3 = 0
= (2x - 1)(2x - 3) = 0
= x = 1/2 x = 3/2
x = 3/2 not possible as then 3 - 2x = 0
so x = 1/2
d²V/dx² = 24x - 24 < 0 for x = 1/2
Hence maximum volume = ( 3 - 2x)²x
= ( 3 - 2×1/2)²(1/2)
= 2 m³
Maximum volume of the tank = 2 m³
#SPJ2
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