Question

ectively. If the difference in interests for two periods was
. Divide 6000 into two parts so that the simple interest on the first part for 9 months at 12% per
annum is equal to the simple interest on the second part for 1 years at 10% per annum.
2
1
1​

Answer 1

Answer:

Let one part is x and other part is (6000−x)

Now,

S.I on first part =S.I. on second part

x×

100

12

×

12

9

=(6000−x)×

100

10

×

2

3

∴x=3750

and (6000−x)

⇒6000−3750=2250

Therefore two parts of 6000 are 3750 and 2250.