Question

Ed can do a piece of work in 8 hours. Edd can do the same work in 10 hours, Eddy can do the sa
work in 12 hours. Ed, Edd and Eddy start the same work at 9 am, while Ed stops at 11 a.m., the
remaining two complete the work. At what time(approx) will the work get completed?
1 a.m.
11.30 am
12 p.m.
1 pm​

Answer 1

• If three persons can do a piece of work in ,x, y ,z hours respectively then all the THREE combined together can do the work in = xyz/(xy +yz +zx)
• So in this problem all the THREE-can complete the work in
• = 8 x 10 x 12/[(8 x10+ (10 x12) + (12 x 8)
• = 960/296 = 3.243 hours.