Question

Ed can do a piece of work in 8 hours. Edd can do the same work in 10 hours, eddy can do the same work in 12 hours. Ed, edd and eddy start the same work at 9 am, while ed stops at 11



a.M., the remaining two complete the work. At what time(approx) will the work get completed

Answer 1

HEY MATE HERE IS YOUR ANSWER

Answer 2

Answer:

The work will be completed by 1 pm.

Step-by-step explanation:

Ed can do the work in 8 hours

Edd can do the work in 10 hours

Eddy can do the work in 12 hours

In one hour:

Ed does $\frac{1}{8}$ of the work.

Edd does $\frac{1}{10}$ of the work.

Eddy does $\frac{1}{12}$ of the work.

Let us denote the fraction of work completed by the three from 9 am to 11 am (2 hours) with A.

A = $2 \times (\frac{1}{8} + \frac{1}{10} + \frac{1}{12})$

  = $\frac{1}{4}+\frac{1}{5}+\frac{1}{6}$

  = $\frac{15 + 12 + 10}{60}$

A = $\frac{37}{60}$

Remaining work, B = 1 - A

                           B  = $\frac{23}{60}$

The fraction of work Edd and Eddy together does in an hour = $\frac{1}{10}+\frac{1}{12}$ = $\frac{6+5}{60} = \frac{11}{60}$

The time required for Edd and Eddy to do the remaining $\frac{23}{60}$ of the work, T = $\frac{23}{60}$÷ $\frac{11}{60}$

T = $\frac{23}{60} \times \frac{60}{11} = \frac{23}{11} \approx 2$

Edd and Eddy requires approximately 2 hours for doing the remaining work. Thus the work can be completed 2 hours after 11 am, i.e. 1 pm.

∴The work will be complete by 1 pm.

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