Question

ed in words are called word
oth word for applied pro
Example 6. Soloe 3(x - 2) = 2(x + 1) - 3.
Solution. Here we should remove the brackets first.
3(x - 2) - 2(x + 1) - 3
3r - 6 = 2x + 2-3
3x = 2x + 2-3 + 6
3x = 2x + 5
3x-2x = 5
x = 5.
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wide variety of word to
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From the above examples, we observe that every linear
has exactly one solution.
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Example 1.15
Solution. Le
128 - 58² 4 mx 7 is
Example 7. Find the value of m if the value of the expression 23
when x = -1.
Solution. Given, the value of 2x - 5x2 + mx - 7 is 10 when
.: 21-1) - 5 (-1)2 + (-1)- 7 = 10
= -2-5-m-7 = 10 -14 - m = 10
= -m= 10 + 14 m = 24 m = -24.
I
5 added to to
Exercise 6.1
1 Solve each of the following equations:
(1) x + 6=8
(11) 2-x=5
(iii) 4x = -6
(id) 7 = 5 (2) 24-3=2
(vi) 4 - 5y = 2
2. Solve the following equations:
(1) 5(x + 1) = 25 (11) 2(3x - 1) = 10 (ii) 37 -1 = 11
3. Solve the following equations:
(1) 5x - 6 = 12 - x (in) 11 + 1 =4-n (in) 5p + 7 = 19 - 22
(iv) 2x + 1 - (0)5 -4 (vi) 18 - 24 = 11 + y.
4. Solve the following equations and verify your answers:
(1) 3 (x + 7) = 18
at the unknown quan
mine which expressions
e the resulting equation
te 1.1f 5 is added to tunica
tion. Let the required mus
ice the number 23,
Aded to twice the numi
cording to the problem
2x + 5 = 29
2x = 29 -5 = 2
Hence, the required nus
Example 2. If thrice a certa
Find the number.
ution. Let the requin
Thrice the number =
Thrice the number
9 more than the nu
According to the p
3x - 7 = x
3x-X=9
Hence, the requir
5
(in) 2 (x - 1) = x + 2
(iv) 4(2x - 1)-2(x-5) = 5(x + 1) + 3
5. Find the value of p if the value of 4 - 3x - px - 5 is equal to 23 when x = -2
Example 3. One-fo
number.
Solution. Let the
Its succeeding
According to
(ii) 3r - 1 = 2 *-) + 5
5x -​

Answer 1

Answer:

Step-by-step explanation:

Example 2: The coefficient of xy in 3x2 zy + 7xyz – 2z2x is

(a) 3z (b) – 2 (c) 7yz (d) 7z

Solution: Correct answer is (d).

Example 3: The factors of the term –xy2 are

(a) x × y × y (b) – 1 × y × y

(c) – 1 × x × y (d) – 1 × x × y × y

Solution: Correct answer is (d).

In Examples 4 to 7, fill in the blanks to make the statements true.

Answer 2

(2x−1)(x−3)=(x+5)(x−1)

$= > 2 {x}^{2} - 6x - x + 3 = {x}^{2} - x + 5x - 5$

$= > {x}^{2} - 11x + 8 = 0$

$= > x = \frac{ - (11) + - \sqrt{( - {11)}^{2} - 4(1)(8)} }{2(1)}$

$x = \frac{11 + - \sqrt{81} }{2}$