Question

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The sum of 4 A.M's between 3 and -7 is
(a) -12
(b) -10A (C) -8​

Answer 1

Answer:

if the 4 AMs are a1,a2,a3,a4 between 3&-7 then common difference is(b-a)/n+1 where a=3andb=-7,n=4we get d =-20so the AMs are 1,-1,-3,-5,and their sum is -8