EF||QR find FR PE=2.5 cm PF=2cm
EQ=4cm FR= ?
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Answer:
The basic proportionality theorem states that if a line is drawn parallel to one side of a triangle and it intersects the other two sides at two distinct points then it divides the two sides in the same ratio.
It is given that PE=3.9 cm, EQ=3 cm, PF=3.6 cm and FR=2.4 cm.
Using the basic proportionality theorem, we have
EQ
PE
=
3
3.9
=1.3
FR
PF
=
2.4
3.6
=1.5
Since
EQ
PE
=
FR
PF
Hence, EF is not parallel to QR.
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