Question

Effect of concentration on the rate of reaction to the volume of potassium iodide and volume of water

Answer 1

Answer:

The reaction occurs in two stages, via an intermediate oxyiodide (OI−−) ion;-

H22O22 (aq) + I−− (aq) ⟶ H22O (l) + OI−− (aq)

H22O22 (aq) + OI−− (aq) ⟶ H22O (l) + O22 (g) + I−− (aq)

Since the iodide ion is not consumed by the reaction, it is classed as a catalyst.

In acid solution there is a different reaction. In the presence of H++ ions, the potassium iodide is oxidised by the hydrogen peroxide into elemental iodine, and the hydrogen peroxide is reduced to water;-

2KI (aq) + 2H++ (aq) + H22O22 (aq) ⟷ I22 (s) + 2H22O (l) + 2K++ (aq)

This reaction is reversible and therefore, unless the iodine is removed from the system, an equilibrium will be reached which will depend on temperature and the initial concentrations of the reactants.

Explanation:

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