Physics, asked by bodom1533, 10 months ago

Effective capacity across ab in the network shown is

Answers

Answered by bestwriters
1

The effective capacity across A and B is 12 μF.

Explanation:

The image given in the question is attached below.

On neglecting the 2μF branch, then the given network is a wheatstone bridge.

Now, there are two branches of series of capacitance.

The capacitors in first branch are 3μF and 6μF.

The capacitors in second branch are 4μF and 8μF.

The equivalent capacitance of first branch is:

\Rightarrow \frac{3 \times 6}{3+6}

\Rightarrow 2 \ \mu F

The equivalent capacitance of second branch is:

\Rightarrow \frac{4 \times 8}{4+8}

\Rightarrow 8/3 \ \mu F

Across A and B, the capacitors of first and second branches are connected in parallel condition.

\Rightarrow (2 + 8/3) \ \mu F

Therefore, capacitance across AB = 12 μF

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