Question

Efficiency of A,B and C is in the ratio 4:5:6. If they together complete the work in 20 days then in how much time A alone can complete the work?

Answer 1

Answer:

Let the numbers be x then,

4x+5x+6x=20

15x=20x=15/20

=3/4×4=3days therefore.a can complete work in 3days

Answer 2

A alone can complete the work in 75 days

Solution:

Given that,

Efficiency of A, B and C is in the ratio 4 : 5 : 6

$Total\ work = Total\ Efficiency \times no.\ of\ days$

$Total\ work = (4+5+6) \times 20 = 15 \times 20$

Total work = 300

So, A alone can complete the work in :

Total Work = Efficiency of A $\times$ no. of days

$\begin{array}{l}{300=4 \times \text { no. of days }} \\\\ {\text { no. of days }=\frac{300}{4}} \\\\ {\text { no. of days }=75}\end{array}$

So, A alone can complete the work in 75 days

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