Question

Efficiency of a heat engine 4 sync is at temperature of 300 kelvin is 40% to increase the efficiency to 60% keeping the sink temperature constant the source temperature must increased by

Answer 1

Temperature of sink () = 300K
Temperature of source = 

Initial efficiency = 40%


If we need to increase the efficiency by 50% of original,
efficiency = 40% + (50/100)×40% = 40%+20% = 60%



Change in temperature = 

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