Question

efficiency of B is two times more than efficiency of A.both started working alternatively,starting with B and completed the work in total 37 days.​if C alone complete the work in 50 days then find in how many days A and C together will complete the work

Answer 1

Answer:

in 30 days A and C together will complete the work

Step-by-step explanation:

B started work then alternately A & B worked for 37 Days

=> B worked for 19 days

& A worked for 18 Days

Let Say Work done by A in 1 Day  = A

B is two times more efficient

=> B 1 day work = A + 2A = 3A

Total Work  done by A & B in 37 days = 19* 3A + 18*A = 75A

C do 75 A in 50 Days

C do in 1 day = 75A/50  = 1.5A

A & C do work  in 1 day = A + 1.5 A = 2.5A

Total Work to be done by A&C = 75A

Number of days required by A &C = 75A/2.5A  = 30

in 30 days A and C together will complete the work