EFGH is a parallelogram. Find x y and z Also, state the properties you use to find them
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Given -
ABCD and EFGH are parallelograms such that ∠A= 120° and ∠G= 70°
To find-
The value of x
Solution -
In parallelogram ABCD,
∠A= ∠C [Opposite angles of a parallelogram are equal] ........1)
And,
∠B= ∠D[Opposite angles of a parallelogram are equal]........2)
Now,
In parallelogram ABCD,
=> ∠A + ∠B + ∠C + ∠D= 360°[Angle sum property of a quadrilateral is 360°]
=> ∠A+ ∠B+ ∠A+ ∠D=360° [by 1) and 2)]
=> 2( ∠A+ ∠B) =360°
=> ∠A+ ∠B= 360°/2
=> 120°+ ∠B=180°
=> ∠B= 180°-120°
=> ∠B= 60°.......3)
Again,
∠G= ∠E=70°[Opposite angles of a parallelogram are equal]........ 4)
Now,
In triangle EPB,
∠E+ ∠P+ ∠B=180°[Angle sum property of triangle is 180°]
=>70°+ x+60°=180°[by 3) and 4)]
=> 130°+x=180°
=> x=180°-130°
=> x =50°
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