Question

EFGH is a parallelogram. Show that the diagonal EG divides the parallelogram into two congruent triangles.​

Answer 1

Answer:

The centre angle is 360 degree. One side of each triangle is 90 degree. They have equal sides (side of square)

Answer 2

Answer:

Given

since EFGH is a parrallelogram therefore EF is parrallel to GH and EH is parrallel to GF

EG is a diagonal

To prove

EFG is congruent to EHG

Step-by-step explanation:

Proof

EF = GH given

EG = EG common

EH = GF given

therefore both triangles are congruent