EFGH is a rhombus. Find the value of x if the m∠FDG=(3x+12)∘
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Answer:
》3x+12=90
》3x=90-12
》3x=78
》x=78/3
》x = 26
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The value of 'x' is 26°
Given:
EFGH is a rhombus.
The measure of ∠FDG=(3x+12)°
To find:
Find the value of x
Solution:
Condition used:
In a rhombus, the diagonals bisect each other at right angles.
Given EFGH is a rhombus.
And the diagonals of the rhombus are intersected at D
The measure of ∠FDG = (3x+12)°
[ For more understanding observe the given picture ]
As we know
The diagonals bisect each other at right angles.
∠FDG = 90°
From the given data,
=> (3x+12)° = 90°
=> 3x = 90° - 12°
=> 3x = 78°
=> x = 26°
Therefore,
The value of 'x' is 26°
Learn more about Rhombus at
https://brainly.in/question/40819156
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