Question

EFGH is a rhombus. Find the value of x if the m∠FDG=(3x+12)∘

Answer 1

Answer:

》3x+12=90

》3x=90-12

》3x=78

》x=78/3

》x = 26

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Answer 2

The value of 'x' is 26°

Given:

EFGH is a rhombus.

The measure of ∠FDG=(3x+12)°

To find:

Find the value of x

Solution:

Condition used:

In a rhombus, the diagonals bisect each other at right angles.  

Given EFGH is a rhombus.

And the diagonals of the rhombus are intersected at D

The measure of ∠FDG = (3x+12)°

[ For more understanding observe the given picture ]

As we know  

The diagonals bisect each other at right angles.  

∠FDG = 90°  

From the given data,

=> (3x+12)° = 90°  

=> 3x = 90° - 12°  

=> 3x = 78°

=> x = 26°

Therefore,

The value of 'x' is 26°

Learn more about Rhombus at

https://brainly.in/question/40819156

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