Math, asked by Chakresh8661, 7 months ago

EFGH is a trapezium with EH parallel to FG. FE and GH are produced (made longer) to meet at J. angle EHF = 62°, angle EFH = 25° and angle JGF = 77°. calculate the size of angle EJH
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Answers

Answered by abhinav394
2

Answer:

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Answered by vj254640
4

Answer:

angle EJH=16 degree

Step-by-step explanation:

EFGH is trapezium - (given)

Now in triangle EFH

angle EFH + angle EHF + angle FEH

25 + 62 + FEH = 180 degree ( angle sum property)

so angle FEH = 93 degree

Now,

angle EHF = angle HFG ( alternate interior angle)

so, angle HFG = 62 degree.

Now ,

angle HEF + EFG + FGH + GHE = 360 degree

(93) + (25+62) + (77) + (62+ FHG) = 360

so, angle FHG = 41 degree.

Again,

FEJ is a line ,

so, angle JEH + angle HEF = 180

JEH + 93 = 180

therefore, angle JEH = 87.

Similarly,

angle JHE = 77.

Now in triangle JEH

angle EJH + JEH + JHE = 180

therefore,

angle EJH = 16 degree.

which is our required angle.

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