Question

Efis diameter seg df is tangent segment the radius of circleis r

Answer 1

Answer:

Step-by-step explanation:

By tangent secant theorem,

DE×DG=DF²

DE×(DE-GE)=DF²

DE²-DE×GE=DF²

(DE²-DF²)=DE×GE ......(By Pythagoras Theorem)

EF²=DE×GE

4r²=DE×GE .......(as EF=2r)

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