Question

Ehat is the kinetic energy required by the electron in hydrogen atom if it absorbs a light radiation of energy 1.08×10^-17

Answer 1

Answer:

EEEEEEEEEEEEEEEEEEE12222222222222222222222222222222222222

Explanation:

Answer 2

Answer:

$K.E. = 6.920\times 10^{-22}$ joules.

Explanation:

Since we have $E = 1.08\times 10^{-17}$...................(1)

we know that

$E = \dfrac{hc}{\lambda}$....................................(2)

$h=6.626\times 10^{-34}$ and $c = 3\times 10^{8}$

so from (1) and (2) we get,

$\lambda = 18.40\times 10^{-9} m$....................(3)

we know the de-brogile relation

$\lambda = \dfrac{h}{mv}$..........................(4)

m = mass of electron

So,from (3) and (4) we get,

$v = 39\times 10^{3} m/s$

we know that the kinetic energy is given by

$K.E = \dfrac{mv^{2} }{2}$

After putting values we get,

$K.E. = 6.920\times 10^{-22}$ joules.