Question

eigen vectors in matrix​

Answer 1

Answer:

t= -2 ; t= [1+-√(-7)]/4

Step-by-step explanation:

Eigen value of 3-by-3

matrix is given by

t^3-tr(A)t+(A11+A22+A33)t-det(A)=0. (1)

tr(A)=(-1)+(-1)+(-1)=-3

A11=1-1=0 ; A22=1-1=0 ; A33=1-1=0

det(A)=(-1)(1-1)-1(-1-1)+1(1+1)=4

put all the values in (1)

t^3+3t^2-4=0. (2)

now by synthetic division

t=-2

remaining term;

-2t^2+t-2=0

2t^2-t+2=0

now by quadratic formula

t=[1+-√(-7)]/4