Eight boys and three girls are to sit in a row for a photograph. Find the probability that no two girls are together.
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Answer:
n[s]= 5
#No Two Girls;
P[E]= n[e] / n [s]
probablity of event = no. of event/no of sectors
P[E]= 8/11.
Answered by
2
Answer:Answer:
n[s]= 5
#No Two Girls;
P[E]= n[e] / n [s]
probablity of event = no. of event/no of sectors
P[E]= 8/11.
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