Question

Eight boys and three girls are to sit in a row for a photograph. Find the probability that no two girls are together.

Answer 1

Answer:

n[s]= 5

#No Two Girls;

                           P[E]= n[e] / n [s]

                            probablity of event = no. of event/no of sectors

                               P[E]= 8/11.

                                       

                     

Answer 2

Answer:Answer:

n[s]= 5

#No Two Girls;

                            P[E]= n[e] / n [s]

                            probablity of event = no. of event/no of sectors

                               P[E]= 8/11.

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