Question

Eight cards bearing number 1. 2, 3, 4, 5, 6, 7, 8 are well shuffled. Then in how many cases the top 2 cards wil form a pair of twin prime equals.? ans-C explain plz

Answer 1

The number of prime in the given series is of 4 that is 1,3,5,7 here sum two prime numbers (1,7) and (3,5) both these will result 8.

So the possibility of two prime pairs can be written in any order.

That’s why more or less top cards are prime numbers.