Question

Eight consecutive numbers are given. if the average of the numbers that appear in the middle is 6, then the sum of eightvgiven numbers

Answer 1

Hello,

Total numbers are 8
Now ,
Let the smallest number be x
So,

The consecutive numbers will be

X, x+1, x+2, x+3,x+4,x+5,x+6,x+7

Now ,
The middle numbers are
X+3 and X+4

Now ,
There average is given 6.
So,
$\frac{x + 3 + x + 4}{2} = 6 \\ \\ 2x + 7 = 12 \\ 2x = 12 - 7 = 5 \\ x = \frac{5}{2} = 2.5$
Now

The numbers are
2.5, 3.5, 4.5, 5.5, 6.5, 7.5, 8.5, 9.5

Sum of all the numbers is 48

So ,
The sum of 8 given numbers is 8

Hope this will be helping you ✌️

Answer 2

Answer:

48

Step-by-step explanation:

in this question we can solve it by simple basic trick

as it is given  the middle number is 6

for example  tere are 5 consecutive numbers like 1 2 3 4 5 then the avg would be the middle number that is 3 the same way in this question

we have 8 numbers

_ _ _ _  6   _ _ _ _

six lies in the middle number so as in the question it is mention that there are eight consecutive numbers which means the diffrence between them is same in this case the diffrence is 1 then we can find the other numbers also

2 3 4 5 (6 lies between 5 and 7 which is the vag  7 8 9 10

now just use the formula  

n/2*(last term +1st term)

8/2*10+2= 4*12=48

done