Question

Eight cubes of side 3cm each are placed end to end, four at the bottom and four on top as shown. find the surface area of the cuboid so formed​

Answer 1

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Answer 2

Given :- Eight cubes of side 3cm each are placed end to end, four at the bottom and four on top as shown. find the surface area of cuboid so formed. ?

Solution :-

Dimensions of cuboid so formed are :-

• Length = sum of sides of 4 identical cubes = 4 * 3 = 12 cm.
• Breadth = side of cube = 3 cm.
• Height = as four are on top , four at bottom , we get = 2 * 3 = 6 cm.

we know that,

• surface area or total surface area of cuboid = 2(length * breadth + breadth * height + height * length) .

putting all values we get,

→ surface area = 2(12 * 3 + 3 * 6 + 6 * 12)

→ surface area = 2(36 + 18 + 72)

→ surface area = 2 * 126

→ surface area = 252 cm². (Ans.)

Hence, the surface area of cuboid so formed is 252 cm².

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