Question

Eight drop of Mercury of equal radii and possessing equal charge combine to form a big drop. the capacitance of bigger drop as compared to capacitance of each individual drop

Answer 1

Explanation:

Capacitance of Smaller drop (say Cs)= 4πεr

where "r" is the radius of the drop and "ε" is the permittivity of space.

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FINDING RADIUS OF BIG DROP:

Now 8 drops combine to form a single large drop .

then using volume conservation :

Volume of Big drop = 8 times the volume of smaller drops.

(4/3)πR³ =8× (4/3)πr³

=> R = 2r

here "R" is the radius of Big drop.

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=> Capacitance of Big Drop (Say Cb) = 4πεR

= 4πε(2r) = 8πεr .

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=> Cb/Cs = 2

=> Capacitance of Big drop is two times than that of smaller drop.

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hope it helps !

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