Eight droplets of water, each of radius 0.2 mm, coalesce into a single drop. Find the change in total surface energy. (Surface tension of water = 0.072N/rn) (Ans : 1.446 x 10⁻⁷ J)
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radius of each droplet , r = 0.2mm
Let R is radius of a single drop which is formed by coalesce of eight droplets.
now, volume of single drop = 8 × volume of each droplet
4/3 πR³ = 8 × 4/3 πr³
R = 2r = 2 × 0.2 mm = 0.4mm
now, change in surface area = 8 × surface area of each droplet - surface area of the single drop
= 8 × 4πr² - 4πR²
= 8 × 4πr² - 4π(2r)²
= 16πr²
now total surface energy = surface tension× change in surface area
= 0.072 N/m × 16πr²
= 0.072 × 16 × 3.14 × (0.2 × 10^-3)²
= 0.072 × 16 × 3.14 × 4 × 10^-8
= 14.469 × 10^-8 J
= 1.469 × 10^-7 J
Let R is radius of a single drop which is formed by coalesce of eight droplets.
now, volume of single drop = 8 × volume of each droplet
4/3 πR³ = 8 × 4/3 πr³
R = 2r = 2 × 0.2 mm = 0.4mm
now, change in surface area = 8 × surface area of each droplet - surface area of the single drop
= 8 × 4πr² - 4πR²
= 8 × 4πr² - 4π(2r)²
= 16πr²
now total surface energy = surface tension× change in surface area
= 0.072 N/m × 16πr²
= 0.072 × 16 × 3.14 × (0.2 × 10^-3)²
= 0.072 × 16 × 3.14 × 4 × 10^-8
= 14.469 × 10^-8 J
= 1.469 × 10^-7 J
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Answer:radius of each droplet , r = 0.2mm
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.now, volume of single drop = 8 × volume of each droplet
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.now, volume of single drop = 8 × volume of each droplet 4/3 πR³ = 8 × 4/3 πr³
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.now, volume of single drop = 8 × volume of each droplet 4/3 πR³ = 8 × 4/3 πr³ R = 2r = 2 × 0.2 mm = 0.4mm
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.now, volume of single drop = 8 × volume of each droplet 4/3 πR³ = 8 × 4/3 πr³ R = 2r = 2 × 0.2 mm = 0.4mm now total surface energy = surface tension× change in surface area
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.now, volume of single drop = 8 × volume of each droplet 4/3 πR³ = 8 × 4/3 πr³ R = 2r = 2 × 0.2 mm = 0.4mm now total surface energy = surface tension× change in surface area = 0.072 N/m × 16πr²
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.now, volume of single drop = 8 × volume of each droplet 4/3 πR³ = 8 × 4/3 πr³ R = 2r = 2 × 0.2 mm = 0.4mm now total surface energy = surface tension× change in surface area = 0.072 N/m × 16πr² = 0.072 × 16 × 3.14 × (0.2 × 10^-3)²
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.now, volume of single drop = 8 × volume of each droplet 4/3 πR³ = 8 × 4/3 πr³ R = 2r = 2 × 0.2 mm = 0.4mm now total surface energy = surface tension× change in surface area = 0.072 N/m × 16πr² = 0.072 × 16 × 3.14 × (0.2 × 10^-3)² = 0.072 × 16 × 3.14 × 4 × 10^-8
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.now, volume of single drop = 8 × volume of each droplet 4/3 πR³ = 8 × 4/3 πr³ R = 2r = 2 × 0.2 mm = 0.4mm now total surface energy = surface tension× change in surface area = 0.072 N/m × 16πr² = 0.072 × 16 × 3.14 × (0.2 × 10^-3)² = 0.072 × 16 × 3.14 × 4 × 10^-8 = 14.469 × 10^-8 J
Answer:radius of each droplet , r = 0.2mm Let R is radius of a single drop which is formed by coalesce of eight droplets.now, volume of single drop = 8 × volume of each droplet 4/3 πR³ = 8 × 4/3 πr³ R = 2r = 2 × 0.2 mm = 0.4mm now total surface energy = surface tension× change in surface area = 0.072 N/m × 16πr² = 0.072 × 16 × 3.14 × (0.2 × 10^-3)² = 0.072 × 16 × 3.14 × 4 × 10^-8 = 14.469 × 10^-8 J= 1.469 × 10^-7 J
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