Physics, asked by kirankumarkumbar30, 4 days ago

Eight drops of mercury of equal. radii combine to form a big drop the capacitance of bigger drop as compared to each smaller drop is?​

Answers

Answered by monipal1984
1

Answer:

Eight drops of mercury of equal radii possessing equal charges combine to from a big drop. Then the capacitance of bigger drop compared to each individual small drop is. As capacity is r, hence capacity becomes 2 times.

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