Question

Eight gram each of oxygen and hydrogen at 27ºC will have the total kinetic energy in the ratio of ............... .

Answer 1

K.E2 for Hydrogen  

No. Of moles of 8g O2 = .25 moles  

No. Of moles of 8g H2 = 4 moles  

KE = 1 / 2nkT; k = R / Na ..... for one mole  

K.E1 / K.E2 = (½n1 RT / Na) / (½n2 RT / Na) ........... Eq 1  

RT / Na cancelled .EQ1 becomes  

K.E1 / K.E2 = .5 n1 / .5n2 = .125 / 2 = 1/16 (1/2 = .5)  

So 1:16

Answer 2

Answer:

1:16

Explanation:

Kinetic Energy=3/2 nRT

apply this formula and solve