Question

Eight guests have to be seated 4 on each side of a long table. 2 particular guests desire to sit on one side of the table and 3 on the other side. The number of ways in which the sitting arrangements can be made is

Answer 1

Thank you for asking this question. Here is your answer:

In this question we are given the 2 choices 1 on side side and the other one on the other side.

First we will focus on the one side

The number of choices we have here are

2! x 3p2 = 2 x 6 = 12

These 2 groups can change their seats among themselves:

So we have 12 x 2 = 24

Now we will come to the other side of the table:

We have 3! x 3C1 = 18 options

So that means the 4th person can take any seat out of 4 seats

So we have 18 x 4 = 72

So 72 x 24 = 1728

1728 is the final answer for this question.

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