Question

Eight small drops,each of radius r and having same charge q are combined to form a big drop. Thae ratio between the potentials of the bigger drop and the smaller drop is what

Answer 1

Answer:

Ratio between potentials of the bigger drop and samller drop = 8

Step by step:

Let the charge on big drop = Q

Redius of big drop = R

Number of small drops = n = 8

Redius of small drop = r

Charge on small drop = q

Now, Charges gets added when multiple drops are combined.

Charge on big drop, is the addition of cahrges o smaller drops.

∴ Q = n×q

∴ Q/q = n

∴ Q/q = 8

Ratio between potentials of the bigger drop and samller drop = 8

∴

Answer 2

Answer:

4:1 and here is your explanation ☝

Explanation:

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