Physics, asked by sreekiranrenati, 8 months ago

eight small mercury droplets each of radius r and having same charge q are combined to form a bigger drop the ratio between the potential of bigger drop and smaller drop is​

Answers

Answered by juhisingh7543287
0

Answer:

v=n^2/3× V here v is considered as potential of small drop ,V is potential of big drop and n is no. of Mercury drop then v=(8)^2/3 ×V ,, v= (2)^2 ×V ,, v=4×V then V/v =1/4 ans

Similar questions