Question

eight term of on A.P. is half the second term and the eleventh term exceeds one-third
of its fourth term by 1 find a15​

Answer 1

Answer:

a15 = 3

Step-by-step explanation:

a + 7d = a + d/2

= 2a + 14d = a + d

a = -13d

a + 10d = 1/3(a + 3d) + 1

a + 10d -1 = 1/3(a + 3d)

3(a + 10d -1) = a +3d

3a + 30d -3 = a + 3d

2a + 27d =3

2(-13d) + 27d =3(since a = -13d)

-26d + 27d = 3

Common Difference (d) = 3

First Term  = -13d

= a = -13*3 = -39

To find the 15th term:

a + 14d = -39 + 42

Hence a15 = 3

Answer 2

Answer:

this is ans

kgjxhxj ,885656*-+68221+-*ap *5554=4578-0q