Question

eight years ago, a mother's age 11 times that of her son. the sum of their present ages is 40 years. find their present ages

Answer 1

Answer:

Let the present age of son be x.

Age of son eight years ago = x-8

Age of mother eight years ago = 11(x-8) = 11x-88

Present age of mother = 11x-88+8 = 11x-80

According to Question,

x+11x-80 = 40

=> 12x = 40+80

=> 12x = 120

=> x = 10

Hence, present age of son = 10 years

Present age of mother = 30 years

Step-by-step explanation: