Eight years ago, ramesh was twice as old as suresh. If the ratio of their ages is 3:2 now, what is suresh's present age?
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Answer:
present age of Suresh = 16
present age of Ramesh = 24
Step-by-step explanation:
*let's assume that past age(8 years ago) of Suresh is "s".
*now we know that 8 years age of Ramesh was 2 times that of Suresh.
_therefore past age of Ramesh = 2"s".
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*Now 8 years later (present age).
2s + 8 3
______________ = ____
s + 8 2
solving this we get,
3s + 24 = 4s + 16
= 4s - 3s = 24 - 16
= s = 8 .
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therefore past age of suresh was 8 and that of ramesh was 16 .
so , there present ages (after 8 years ) is
ramesh = 24
suresh = 16.
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