Math, asked by manjotk7191, 11 months ago

Eight years ago, ramesh was twice as old as suresh. If the ratio of their ages is 3:2 now, what is suresh's present age?

Answers

Answered by niladripramanick9
0

Answer:

present age of Suresh = 16

present age of Ramesh = 24

Step-by-step explanation:

*let's assume that past age(8 years ago) of Suresh is "s".

*now we know that 8 years age of Ramesh was 2 times that of Suresh.

_therefore past age of Ramesh = 2"s".

___________________________________________

*Now 8 years later (present age).

2s + 8 3

______________ = ____

s + 8 2

solving this we get,

3s + 24 = 4s + 16

= 4s - 3s = 24 - 16

= s = 8 .

_______________________________

therefore past age of suresh was 8 and that of ramesh was 16 .

so , there present ages (after 8 years ) is

ramesh = 24

suresh = 16.

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