Question

Eight years ago the father age was three times that of his sons ,but two years hence the father age would be twice that of the sons .Find the present age of the father and the son.


plzzzz help​

Answer 1

Answer:

let father present age be x years and son present age y years.

Eight years ago

Father age = x - 8

Since age = y - 8

so,x - 8 = 3(y - 8)

x - 8 = 3y - 24

x = 3y - 16 ........(1)

After 2 years,

Father age = x + 2

Son age = y + 2

so, x + 2 = 2(y + 2)

3y - 16 + 2 = 2y + 4

y = 18

so, x= 3(18) - 16 = 54 - 16 = 38