Math, asked by tinnysaha2009, 1 month ago

Eighteen integers are multiplied together. What will be the sign of there product, if: (i) 15 of them are negetive and 3 are positive? (ii) 12 of them are negetive and 6 are positive? (iii) 9 of them are positive and the remaining are negetive? (iv) all are negetive?​

Answers

Answered by reyanshgoelrobogami
0

Answer:

Step-by-step explanation:

(i) Since out of 18 integers, 15 of them are negative,which is odd in number. Hence, the sign of the product of 15 negative integers and 3 positive integers will be negative.

(ii) Since out of 18 integers,12 of them are negative, which is even in number. Hence, the sign of the product of 12 negative integers and 6 positive integers will be positive.

(iii) Since out of 18 integers, 9 are negative, which is odd in number. Hence, the sign of the product of 9 negative integers and 9 positive integers will be negative.

(iv) Since all are negative,which is even in number. Hence , the sign of their product will be positive.

Answered by harshitscienceandvin
0

Step-by-step explanation:

(i) the sign of the product is negative

(ii) the sign of the product is positive

(iii) the sign of the product is negative

(iv) the sign of the product is positive

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