Math, asked by elsami1040, 1 year ago

Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ?
A) 84 yrs
B) 96 yrs
C) 116 yrs
D) 108 yrs

Answers

Answered by Anonymous
0
Eighteen years ago, a mother was three times as old as her daughter. Now the mother is only twice as old as her daughter. Then the sum of the present ages of daughter and the mother is ?
A) 84 yrs
B) 96 yrs
C) 116 yrs
D) 108 yrs

Answer: D)108 yrs
Answered by Anonymous
0
Let x equal the daughter’s current age. The mother’s age 6 years ago was equal to 5(x - 6). The mother’s current age is given as 3x. The equation to solve is:

5(x - 6) = 3x

5x - 30 = 3x

-30 = -2x

15 = x

Since the mother’s age is now 3 times the daughter’s age and the daughter is now 15, the mother is 45.

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