Question

eighteen years ago the ratio of A 's age to B's was 8:13. their present ratio is 5:7; What is the present age of A.​

Answer 1

Answer:

AGE OF A

Step-by-step explanation:

let x = the multiplier

then

5x = A's present age

and

7x = B's present age

:

18 years ago:

%28%285x-18%29%29%2F%28%287x-18%29%29 = 8%2F13

cross multiply

13(5x-18) = 8(7x-18)

65x - 234 = 56x - 144

65x - 56x = -144 + 234

9x = 90

x = 90/9

x = 10 is the multiplier

then

A = 5(10)

A = 50 yrs old now

:

:

Confirm this solution, find B's age; 10*7 = 70yrs old

Answer 2

Answer:

$A= 50 \: years \\ B=70 \: years$

Step-by-step explanation:

It is the correct answer.