Eighth and Fourteenth terms of an arithmetic sequence are 64 and 88 respectively then find first term ?
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thefirst term is 36 and common difference is 4
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The first term(a) =36 and the common difference (d) = 4
As we take the 8th term as , a+ 7d and the 14th term as ,a+13d
By using simultaneous equation method, we find ‘a’ and ‘d’
As we take the 8th term as , a+ 7d and the 14th term as ,a+13d
By using simultaneous equation method, we find ‘a’ and ‘d’
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