Question

Eind the least number which when
increases by, I5 is excactlydivisible
by 15, 35,48​

Answer 1

Answer:

LCM 0F 15, 35, 48 = 1680

REQUIRED NO = 1680-15 = 1665

Step-by-step explanation:

Answer 2

Let the number be x.

The number when increased by 15, becomes x+15.

The number is 1665.

The least number that is exactly divisible by 15, 35 and 48 is their LCM. So the LCM of 15 , 35 and 48 is 1680. If we decrease 1680 by 15 the result is 1665. So 1665 is the least number which when increased by 15 will be divisible by 15, 35 and 48.

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