Question

Eind the zeroes of the quadratic
Polynomial x² - 2x -8​

Answer 1

Answer:

Step-by-step explanation

X^2-2x-8

=x^2-4x+2x-8 (factorization)

=x(x-4x)+2(x-4) (common factors)

=(x-4)(x+2)

X-4=0 x+2=0

X=4 x=-2

4&-2 are the zeros of quadratic polynomial

Answer 2

Step-by-step explanation:

$x ^{2} - 2x - 8$

$x ^{2} - 4x + 2x - 8$

$x(x - 4) + 2(x - 4)$

$(x - 4)(x + 2)$

x = (-2,4)