Question

Einor Test-03_25-10-2020 (UT JEE-
322)
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If the roots of the equation 2x2 - 3x + 5 = 0 are reciprocals of the roots of the
equation ax? +bx+2 = 0, then
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(1) a= 2 b=3
[2] a = 2,b=-3
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[3] a =5,b= -3
[4] a= 5,b=3
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Oponse​

Answer 1

what type of Q is this?

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Answer 2

Answer:

a = - 5, b = - 3

Step-by-step explanation:

2x² - 3x - 5 = 0

D = 9 + 40 = 7²

$x_{1}$ = - 1

$x_{2}$ = 5/2

(2/5)²a + (2/5)b + 2 = 0 ⇔ 4a + 10b = - 50 ..... (1)

(- 1)²a + (- 1)b + 2 = 0 ⇔ a - b = - 2 ..... (2)

(1) + 10 × (2)

14a = - 70 ⇒ a = - 5

- 5 - b = - 2 ⇒ b = - 3