Question

Eis a point on side AC of AABC with AB = AC. Show that CE<BE.​

Answer 1

Answer:

Given - AB = AC

To prove -- BD > CD

Proof -- Since AB = AC

∠ABC = ∠ACB  (By Isosceles Triangle property) ----(i)

Here clearly,

∠ABC > ∠CBD

∠ACB > ∠CBD ---from (i)

∠DCB > ∠CBD

BD > CD   (Angle opposite to greater side is greater in a triangle)

Hence Proved!

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