Question

ek 20 meter lambi sidhi khadi diwar par tiki hai.yah zamin k sath 6 digree ka kon banati hai.diwar se sidhi ke pairo ke beech ki duri gyat kijiye​

Answer 1

Given:

A  20 m long ladder leaning against a wall makes an angle of 60° with the ground.

To find:

The distance of the foot of the ladder from the wall.

Solution:

Let's assume,

"AB" → the height of the wall

"AC" → the length of the ladder = 20 m

"BC" → the distance between the foot of the ladder and the wall

"∠ACB = 60°" → the angle made by the ladder with the ground

In Δ ABC, we have

$cos \:60\° = \frac{Base}{Hypotenuse}$

$\implies cos \:60\° = \frac{BC}{AC}$

$\implies \frac{1}{2} = \frac{BC}{20}$

$\implies BC = \frac{20}{2}$

$\implies \bold{BC = 10\:m}$

Thus, the distance between the foot of the ladder and the wall is → 10 m.

-------------------------------------------------------------------------------

Also View:

A ladder is leaning against the side of the house the ladder is 4.2 m long and the base of the ladder is 1.3 m from the side of the house. How far up does the ladder reach?

https://brainly.in/question/17061864

A ladder leaning against a wall makes an angle of 60° with the ground. if the length of the ladder is 19 m. find the distance of the foot of the ladder from the wall.

https://brainly.in/question/2991506

A ladder of length 6 m makes an angle of 30° with the floor while leaning against one wall of a room. If the foot  of the ladder is kept fixed on the floor and it is made to lean against the opposite wall of the room, it makes an  the angle of 60° with the floor. Find the distance between the two walls of the room.

https://brainly.in/question/23800478

Answer 2

Given:

A  20 m long ladder leaning against a wall makes an angle of 60° with the ground.

To find:

The distance of the foot of the ladder from the wall.

Solution:

Let's assume,

"AB" → the height of the wall

"AC" → the length of the ladder = 20 m

"BC" → the distance between the foot of the ladder and the wall

"∠ACB = 60°" → the angle made by the ladder with the ground

In Δ ABC, we have

$cos \:60\° = \frac{Base}{Hypotenuse}$

$\implies cos \:60\° = \frac{BC}{AC}$

$\implies \frac{1}{2} = \frac{BC}{20}$

$\implies BC = \frac{20}{2}$

$\implies \bold{BC = 10\:m}$

Thus, the distance between the foot of the ladder and the wall is → 10 m.

-------------------------------------------------------------------------------