ek a.p. me 50 pad hai jiska tisara pad 12 hai or antim pad 106 hai iska 29 pad gyat kijiye
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2
Answer:
i dont know ok ok ok this is hard
Answered by
1
Step-by-step explanation:
n= 50
A3 = A + 2D , A+ 2D = 12 (given) (first eq.)
A(n) that is A(50)
A(50)= A + 49D , that is A+ 49D = 106 (given) (second eq.)
subtracting eq 1 and 2
we get A+ 2d=12
A + 49D = 106
- - -
----------------------------
- 47 D = - 94
D = -94÷ -47 = 2 ,D= 2
putting value of d in 1 eq
we get A= 8
therefore,
A29 = 8 + 28×2 = 8+ 56 = 64 is the ans
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