ek bhai apni bahan ke paas gya. bahan ne bhai ke jeb mein utne hi paise daal diye jitne ki uske paas the.bhai ne bahan ko usme se 2000 rs de diye.ab dusri bahan ke paas gya aur dusri bahan nebhi utne hi paise jeb mein daal diye jitne ki uske paas the.bhai nedoosri ko bhi 2000 rs diye.ab bhai 3bahan ke paas gya 3 bahan nebhi utne hi paise bhai ke jeb mein daal diye jitne ki uske paas the.phir bhai ne 3 bahan ko bhi 2000 rs diya.ant mein bhai ke paas 5000 rs bacha.to batao bhai ke paas jeb mein kitne paise the.
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Let the brother be "B", three sisters be "S1", "S2" AND "S3".
Now, let us assume that B had Rs x initially.
As per the question,
After visiting S1, amount with B = x + x - 2000= Rs (2x - 2000).
Similarly, after visiting S2, amount with B = 2 * (2x - 2000) - 2000 = 4x - 6000.
After visiting S3, amount with B = 2 * (4x - 6000) - 2000 = 8x - 14000.
Now, ATP 8x - 14000 = 5000.
or, 8x = 5000 + 14000 = 19000.
or, x = 2375.
Therefore, the brother had with him Rs 2375 at the very beginning.
I, hope the solution is clear to you, if not please ask.
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